45-10x+5-5x=5x^2

Solution for 45-10x+5-5x=5x^2 equation:

45-10x+5-5x=5x^2

We move all terms to the left:

45-10x+5-5x-(5x^2)=0

determiningTheFunctionDomain
-5x^2-10x-5x+45+5=0

We add all the numbers together, and all the variables

-5x^2-15x+50=0

a = -5; b = -15; c = +50;
Δ = b2-4ac
Δ = -152-4·(-5)·50
Δ = 1225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1225}=35$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-35}{2*-5}=\frac{-20}{-10}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+35}{2*-5}=\frac{50}{-10}
=-5
$